Reading xml files from a zipped file

[rutledj]

I have a channel that reads in a zipped file contains multiple XML files. I'm able to upzip, read, and process files to another channel. My issue is that I need a way to maintain the original file name so the 2nd channel can use that as the file name when it writes it out. Below is my code in the source javascript reader.

var File = Packages.java.io.File;
var FileInputStream = Packages.java.io.FileInputStream;
var ZipInputStream = Packages.java.util.zip.ZipInputStream;
var ByteArrayOutputStream = Packages.java.io.ByteArrayOutputStream;
var childChannelId = 'zip child channel';
var zipDir = new File("C:/Users/azmirth.mrutledge/Documents/");
var files = zipDir.listFiles();

var ByteArrayInputStream = Packages.java.io.ByteArrayInputStream;
var ZipInputStream = Packages.java.util.zip.ZipInputStream;
var ByteArrayOutputStream = Packages.java.io.ByteArrayOutputStream;

// DOM imports
var DocumentBuilderFactory = Packages.javax.xml.parsers.DocumentBuilderFactory;
var TransformerFactory = Packages.javax.xml.transform.TransformerFactory;
var DOMSource = Packages.javax.xml.transform.dom.DOMSource;
var StreamResult = Packages.javax.xml.transform.stream.StreamResult;
var StringWriter = Packages.java.io.StringWriter;

if (!files || files.length == 0)
{
    return null;
}


for each (var file in files) 
{

    if (!file.getName().toLowerCase().endsWith(".zip")) {
        continue;
    }
	var zis = new ZipInputStream(new FileInputStream(file));
	
	var buffer = java.lang.reflect.Array.newInstance(java.lang.Byte.TYPE, 16384);
	var entry;
	
	while ((entry = zis.getNextEntry()) != null) 
	{
	
	    if (!entry.isDirectory() && entry.getName().toLowerCase().endsWith(".xml")) 
	    {
	
	        //Read ZIP entry into memory
	        var baos = new ByteArrayOutputStream();
	        var len;
	
	        while ((len = zis.read(buffer)) > 0) 
	        {
	            baos.write(buffer, 0, len);
	        }
	
	        //Convert to clean XML string
	        var xmlString = new java.lang.String(baos.toByteArray(), "UTF-8").trim();
	
	        //Parse XML with DOM
	        var factory = DocumentBuilderFactory.newInstance();
	        factory.setNamespaceAware(true);
	        var builder = factory.newDocumentBuilder();
	
	        var doc = builder.parse(new ByteArrayInputStream(xmlString.getBytes("UTF-8")));
	
	        //Convert back to string
	        var transformer = TransformerFactory.newInstance().newTransformer();
	        var writer = new StringWriter();
	
	        transformer.transform(new DOMSource(doc), new StreamResult(writer));
	
	        var cleanXml = writer.toString();
	
	        //Route to child channel
	        router.routeMessage(childChannelId, wrapped);
	    }
	
	    zis.closeEntry();
	}
}
zis.close();
return null;

[rutledj]

So I thought I could just put the filename inside a new element in the xml document. I tried this:

 var fileName = entry.getName();
var newElement = <fileName> + fileName.toString() + </fileName>;
xmlObj.appendChild(newElement);

but it dosn't actually put the filename, just what I typed:

  </component>
    <fileName xmlns=""> + fileName.toString() + </fileName>
</ClinicalDocument>

How do I create a xml child with the value of a variable in it?